Question

Ten years ago father was 12times the age of son. Ten year hence father is twice the age of son. find the age of father​

Answer 1

Answer:

Father is 34 years old

Step-by-step explanation:

Father's age now- f

Son's age now- s

Given

Ten years ago- f-10= 12(s-10) => f=12s - 110

Ten years hence- f+10=2(s+10) => f=2s +10

Comparing the two equations above:

12s-110=2s+10

10s=120

s=12- son's age

Father's age = 2s+10=2*12+10=34

Answer 2

let son's age be x

let father's age be y

y-10 =12(x-10)

y-10=12x-120

y-12x=-110

y+10=2(x+10).

y+10=2x+20

y=2x+10

y-12x=-110

2x+10-12x=-110

-10x=-120

x=-120/-10=120/10

x=12

y=2x+10

28*12+10

24+10=34 yrs