Ten years ago father was twelve times as old as his son and ten years hence he will be twice as old as his son will be. find their present ages
Answers
Answered by
1
Father's age = 34
Son's age = 12
Answered by
5
Answer:
Let,
the Present age of the Son = x years
the Present age of the Father = y years
Acocording to the Conditions,
y - 10 = 12 ( x - 10) → 12x - y = 110...............1)
y + 10 = 2 ( x + 10 ) → 2x - y = -10 ................2)
Subtracting 2) from 1), we get
x = 12
Substituting the value of x = 12 in equation 2), we get
y = 34
Therefore the Present age of Son and Father is 12 years and 34 years respectively.
Step-by-step explanation:
Similar questions