Question

ten years ago father was twelve times as old as his son and ten years tense he will be twice as old as his son will be find his present age

Answer 1

let the present age be x
x - 10 = 2{12 x + 10}
x - 10 = 24x + 20
-10+20 = 24x- x
10 = 23x
10 / 23 =x
find the ages