Question

Ten years ago , father was twice as old as his son and ten years hence , he

will be twice as old as his son will be. find their present ages​

Answer 1

Answer:

After 10 years, father's age will be (x+10) years and son's age will be (y + 10) years. Also again from the question it's given as, Before 10 years, the age of father was (x – 10) years and the age of son was (y – 10) years. Hence, the present age of father is 34 years and the present age of the son is 12 years