Math, asked by rohitbhai1614, 9 months ago

Ten years ago, Mohan was half of krishnas' age. If the ratio of their ages is 3:4 . What is krishnas' age

Answers

Answered by ashiahussain139
2

Answer:

37

Step-by-step explanation:

mohan age :3x

Krishna's age: 4x

(3x-4x)=1/2(4x-10)

3x-10=2x-5

x=5

total of their present age =3x+4x=7x= 7×5=35

Answered by BrainlyRaaz
6

Given :

  • Ten years ago, Mohan was half of krishna's age.

  • The ratio of their ages is 3:4

To find :

  • Krishna's age =?

Step-by-step explanation:

Let the Krishna's age be 2x.

And, Mohan was half of krishna's age,

So, Mohan's age = 2x/2 = x

After 10 years Krishna's age = 2x + 10

After 10 years Mohan's age = x + 10

According to the question :

➮ x + 10 / 2x + 10 = 3/4

➮ 4 (x + 10) = 3 ( 2x + 10)

➮ 4x + 40 = 6x + 30

➮ 4x - 6x = 30 - 40

➮ -2x = - 10

➮ x = - 10/ - 2

➮ x = 5.

Therefore, We know that value of x = 5

Hence,

Krishna's age = 2x = 2 × 5 = 10 year's


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