Ten years ago, p was half of q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?
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let present age of p and q be x and y respectively.
ten years ago their ages were x-10 and y-10.
A.T.Q
Age of p= 1/2(age of q)
2(x-10) = y-10
2x-20 = y-10
2x-y = 10 :1 × 3
6x -3y = 30 :2
Now ,ratio of present age of p and q is 3:4
x/y=3/4
4x-3y= 0 : 3
eq 3-2
2x=30
x= 15
putting x= 15 in 1
y=20
present age of p is 15 and q is 20
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ten years ago their ages were x-10 and y-10.
A.T.Q
Age of p= 1/2(age of q)
2(x-10) = y-10
2x-20 = y-10
2x-y = 10 :1 × 3
6x -3y = 30 :2
Now ,ratio of present age of p and q is 3:4
x/y=3/4
4x-3y= 0 : 3
eq 3-2
2x=30
x= 15
putting x= 15 in 1
y=20
present age of p is 15 and q is 20
plz mark as brainliest
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