Math, asked by rishabh8463, 4 months ago

Ten years ago, P was half of Q's age. If the ratio of their present ages is 3:4, what will be the total of their present ages?

Answers

Answered by swaraj01
0

Answer:

35

Step-by-step explanation:

Let the present age of P and Q be 3x and 4x respectively.

Let the present age of P and Q be 3x and 4x respectively.Ten years ago, P was half of Q in age

Let the present age of P and Q be 3x and 4x respectively.Ten years ago, P was half of Q in age=> 2(3x – 10) = (4x – 10)

Let the present age of P and Q be 3x and 4x respectively.Ten years ago, P was half of Q in age=> 2(3x – 10) = (4x – 10)=> 6x – 20 = 4x – 10

Let the present age of P and Q be 3x and 4x respectively.Ten years ago, P was half of Q in age=> 2(3x – 10) = (4x – 10)=> 6x – 20 = 4x – 10=> 2x = 10

Let the present age of P and Q be 3x and 4x respectively.Ten years ago, P was half of Q in age=> 2(3x – 10) = (4x – 10)=> 6x – 20 = 4x – 10=> 2x = 10=> x = 5

here is ur answer....

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