Math, asked by omprakash932738, 3 months ago


Ten years ago. P was half of Q's age.If the ratio of their present ages is 3:4. What will be
the total of their present ages?​

Answers

Answered by anirbanbhukta551
0

Answer:

Your answer is - 35 years

Attachments:
Answered by GODLYxCHAOS
0

Answer:

P is 15 years old, Q is 20 years old.

The sum total of their present ages is 35 years.

Step-by-step explanation:

Let P and Q's present ages be 3x years and 4x years, respectively.

10 years ago, their ages were (3x - 10) years and (4x - 10) years, respectively.

B.T.P.

1/2 of (4x - 10) = 3x - 10

⇒ 4x - 10 = (3x - 10) × 2 = 6x - 20

⇒ 4x = 6x - 20 + 10

⇒ 4x - 6x = (-10)

⇒ -2x = -10

⇒ x = 10/2                   [multiplying both sides with -1)

⇒ x = 5

P's present age = 3x = 3 × 5 = 15 years

Q's age = 4x = 4 × 5 = 20 years.

Please mark this as brainliest.

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