Question

Ten years ago p was half of q's age.If the ratio of their present age is 3:4, what will be the total of their present agez?

Answer 1

Let the present age of P and Q be 3x and 4x respectively.
Ten years ago, P was half of Q in age
=> 2(3x – 10) = (4x – 10)
=> 6x – 20 = 4x – 10
=> 2x = 10
=> x = 5

3x= 15
4x= 20

so the total of there present ages is 15+20= 35

Answer 2

Answer:

The total of P and Q's present age is 35.

Step-by-step explanation:

Given 10 years ago P was half of Q's age.

The ratio of P and Q's present age is 3:4.

Let the present age of P be 3x and of Q be 4x.

Age of P and Q before 10 years can be given as 3x – 10 and 4x – 10 respectively.

10 years ago, P was half of Q in age, this can be written as  

$3x-10 = \dfrac{4x -10}{2}$  

$\implies 2(3x - 10) = (4x -10)$

$\implies 6x - 20= 4x -10$

$\implies 6x - 4x= 20 -10$

$\implies 2x = 10\implies x=\dfrac{10}{2} =5$

Thus P's present age is $3x=3\times 5=15$

And Q's present age is $4x=4\times 5=20$

And the sum of their present ages is $15+20= 35$

Therefore, the total of P and Q's present age is 35.