Ten years ago Prisha age was square of her sisters age . Eleven years hence she will be six years older then her sister .find their present age
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Let the present age of Prisha's sister be x and present age of Prisha be y
(y-10) = (x-10)^2
y-10 = x^2 -20x +100
y= x^2-20x+ 110
y+11 = x+17
y= x+6
x^2 - 20x+ 110= x+6
x^2 -21x + 104=0
(x-13) (x-8)
x= 13 or 8
x cannot be equal to 8 as ten years ago her age will become negative
Therefore
Prisha's sister's present age =13
Prisha's present age= 19
(y-10) = (x-10)^2
y-10 = x^2 -20x +100
y= x^2-20x+ 110
y+11 = x+17
y= x+6
x^2 - 20x+ 110= x+6
x^2 -21x + 104=0
(x-13) (x-8)
x= 13 or 8
x cannot be equal to 8 as ten years ago her age will become negative
Therefore
Prisha's sister's present age =13
Prisha's present age= 19
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