Math, asked by nehasrip24, 9 months ago

ten years ago the age of a father is four times of father

Answers

Answered by VaibhavTheAryabhatta

1

Answer:

Let the present age of father be x

Ten years ago, father's age = x-10 years

ACQ,

4(x-10) = x

4x - 40 = x

3x = 40

x = 40/3 years

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