ten years ago the age of a father was four times of his son. ten years hence the age of the father will be twice that of his son the present ages of father and son are
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Answered by
27
x+10=2x
2x=x+10
2x-x=10
x=10 years
y=2x
y=2*10
=20 years
x is the age of son and y is the age of father
2x=x+10
2x-x=10
x=10 years
y=2x
y=2*10
=20 years
x is the age of son and y is the age of father
Answered by
40
F-10=4(S-10) on solving this one gets F-4S=-30....1
F=10=2(S+10) on solving this one gets F-2S=10....2
solve both the equation and you get F=50 S=20
F=10=2(S+10) on solving this one gets F-2S=10....2
solve both the equation and you get F=50 S=20
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