Question

Ten years ago, the age of a man was 35 years more
than twice his son's age. After how many years from
now will the man be
(i) twice his son's age?
(A) 15
(B) 20
(C) 25
(D) Cannot be determined​

Answer 1

Answer:

Correct option is

A

15

Let the son's age be x

Then according to given data

Father's age y=3x+35−−−−−−(1)

Present age of father =y+10

Present age of son =x+10

After t numbers of years, father be twice his son's age.

y+10+t=2(x+10+t)

On simplifying, t=y−2x−10

By (i)t=35−10=25

After 25 years father will be twice his son's age