Question

Ten years ago, the age of a man was four times that of his son. Five years ago, the age of the man was three times that of his son. Find their present ages.

Answer 1

Answer:

20yrs, 50yrs

Step-by-step explanation:

Let the age of the man be a and age of son be b

According to the question, (a-10)=4(b-10)

simplifying, a - 10 = 4b - 40

4b - a = 30                (equation 1)

second equation is (a-5)=3(b-5)

simplifying, a - 5 = 3b - 15

3b - a = 10                  (equation 2)

equation 1 - equation 2

4b - a -3b + a = 20

b = 20

a = 3b - 10 = 50

Therefore, age of the man is 50yrs and that of his son is 20yrs