Ten years ago, the age of a man was four times that of his son. Five years ago, the age of the man was three times that of his son. Find their present ages.
Answers
Answered by
1
Answer:
20yrs, 50yrs
Step-by-step explanation:
Let the age of the man be a and age of son be b
According to the question, (a-10)=4(b-10)
simplifying, a - 10 = 4b - 40
4b - a = 30 (equation 1)
second equation is (a-5)=3(b-5)
simplifying, a - 5 = 3b - 15
3b - a = 10 (equation 2)
equation 1 - equation 2
4b - a -3b + a = 20
b = 20
a = 3b - 10 = 50
Therefore, age of the man is 50yrs and that of his son is 20yrs
Similar questions