Question

.Ten years ago, the age of a person’s mother was three times the age of her son. Ten years hence, the mother’s age will be two times the age of her son. The ratio of their present ages will be:

A) 10:19 B) 9: 5 C) 7: 4 D) 7: 3​

Answer 1

Answer:

answer is 7:4

I hope it's right

Answer 2

♡ Heya user ♡

Given :-

▪Ten years ago, the age of a person’s mother was three times the age of her son. Ten years hence, the mother’s age will be two times the age of her son.

To Find :-

▪ The ratio of their present age.

Solution :-

✰According to 1st condition:-

Let the age of the son ten years ago be x years.

&

the age of the mother will be 3x years.

Hence, the present age of the son will be x+10 years.

& the age of the mother will be 3x+10 years.

✰According to 2nd condition :-

After ten years,

the mother's age will be 3x+10+10

& the son's age will be x +10+10

✰As per the question, we have :-

(3x+10)+10 = {2 ( x+10) +10}

➯ 3x +20 = 2x +40

➯ x = 20

Therefore,

The present age of the mother

= 3(20) + 10

=70 years

The present age of the son

= 20 +10

= 30 years

Hence, the ratio is 7:3.

That's why, the correct option is D) 7:3

✧ Thanks ✧