Question

Ten years ago, the age of a person’s mother was three times the age of her son. Ten years hence, the mother’s age will be two times the age of her son. Then find the ratio of their present ages

Answer 1

Solution:

let son's present age = x year

10 year ago son's age was (x-10) year

10 year ago mother's age was 3(x-10) year

now 10 year hence son's age will be (x+10) year and mother's age will be 2(x+10) year or 3(x-10)+20 year.

according to the equation

2(x+10) = 3(x-10)+20

2x+20 = 3x-10

and x = 30 year

so son's present age is 30 year and mother's present age is 70 year.

ratio of son's present age and mother's present age = 30:70 = 3:7.

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