Math, asked by BrainliestQuestion, 18 days ago

Ten years ago, the age of a person’s mother was three times the age of her son. Ten years hence, the mother’s age will be two times the age of her son. Their present ages are​

Answers

Answered by abhaysingh27052019
0

Answer:

their parent age are 89years because

Step-by-step explanation:

10 + 60

70 + 10

= 80

Answered by IISLEEPINGBEAUTYII
1

According to 1st condition:

Let the age of the son ten years ago be x years.

&

the age of the mother will be 3x years.

Hence, the present age of the son will be x+10 years.

& the age of the mother will be 3x+10

years.

✩According to 2nd condition :

After ten years,

@77

the mother's age will be 3x+10+10 & the son's age will be x +10+10

✩As per the question, we have

✩As per the question, we have :

(3x+10)+10 = {2 (x+10) +10}

@77

3x +20= 2x +40

⇒x=20

Therefore,

The present age of the mother

= 3(20) + 10

=70 years

The present age of the son

= 20 +10

= 30 years

Hence, the ratio is 7:3.

That's why, the correct option is D) 7:3

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