Question

ten years ago, the age of divya was half of the age os namrata .if the ratio of present ages of both is 3 :4 the sum of their present ages is

Answer 1

d - 10 = n/2

3:4::d:n

so,

4d = 3n

4d/3 = n

d - 10 = 4d/3* 1/2

d - 10 = 4d/6

d - 10 = 2d/3

d - 2d/3 = 10

(3d-2d)/3 = 10

d/3 = 10

d = 30  , n = 30/2 = 15

d = divya , n = namrata

Answer 2

Answer:

d - 10 = n/2

3:4::d:n

so,

4d = 3n

4d/3 = n

d - 10 = 4d/3* 1/2

d - 10 = 4d/6

d - 10 = 2d/3

d - 2d/3 = 10

(3d-2d)/3 = 10

d/3 = 10

d = 30  , n = 30/2 = 15

d = divya , n = namrata

Step-by-step explanation:

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