Question

Ten years ago the age of father was 4 times of his son. Ten years hence the age of father will be twice that of his son. The present ages of the father and the son are:

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20