Math, asked by agmail1412, 1 year ago

Ten years ago the age of father was four times of his son.ten years hence the age of the father will be twice that of his son. The present age of the father and the son are

Answers

Answered by SonOfSubair
5
hope you understand it..
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Answered by PixleyPanda
1

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20

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