Ten years ago the age of father was four times of his son.ten years hence the age of the father will be twice that of his son. The present age of the father and the son are
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Step-by-step explanation:
let the father's age be 4x and son's age be x
after 10years
4x + 10 = 3 *(x+ 10)
4x+10= 3x +30
4x -3x = 30-10
x= 20
therefore father's present age = 4x
=4 * 20 = 80
son's present age = x=20
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