Question

Ten years ago the age of father was four times that of his son. Five years ago, the age of father was three times of his son. Find present age of father and his son.​

Answer 1

let the present age of father =x+10

the present age of his son =y+10

case 1,

ten years ago,

x+10=4(y+10)

x+10=4y+40

x - 4y=40-10

x - 4y=30 _______eq1

case 2

five years ago,

x+10=3(y+10)

x+10=3y+30

x - 3y=30-10

x - 3y=20_______eq2

division eq 1from eq 2

x - 4y=30

x - 3y=20

__________

- y= 10

y=10

x - 4y=30

x - 4(10)=30

x - 40 =30

x= 30+40

x=70.

I hope it's help you!