ten years ago the age of father was three times that of his son ,ten years after father age will be two times that of his son, present age ratio of the father and son is?
Answers
Answer:
Age ratio of father and son's age is 70 : 30
Explanation:
Given, ten years ago father was three times his son's age.
If we assume son's age ten years ago as x
Then, father's age is 3x
And also, the present age of :-
- Son = (x + 10) years.
- Father = (3x + 10) years.
Now, 10 years hence, their age would be :-
- Son's age = (x + 20) years.
- Father's age = (3x + 20) years.
According to the question,
Father is now twice the son's age.
∴ 3x + 20 = 2(x + 20)
Solving further,
⇒ 3x + 20 = 2x + 40
⇒ 3x - 2x = 40 - 20
⇒ x = 20
∴ x = 20
Hence, the present age of :-
- Son = (x + 10) = 30 years.
- Father = (3x + 10) = 70 years.
Forming in ratio :-
⇒ Father's age : Son's age
⇒ 70 : 30
∴ Required ratio :- 70 : 30
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Quick check :-
We have, Father's age 70 years and son's age 30 years.
Given, 10 years ago father was thrice the age of son
10 years ago father's age was 70 - 10 = 60 years
And son's age was = 30 - 10 = 20 years.
Clearly, 60 is thrice 20
And also, it is given that 10 years later father will be twice the age of son.
10 years hence, the age of father would be 70 + 10 = 80 years and son's age would be 30 + 10 = 40 years
Clearly, 2 times 40 gives us 80.
Checked!!
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Answer:
Correct option is B)
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x+10)+10=2[(x+10)+10]
⇒3x+20=2x+40
⇒x=20
∴ Required ratio =(3x+10):(x+10)=70:30=7:3
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