Question

Ten years ago, the age of mother was three times the age of her son. After ten years, mother's age will be twice that of his son. Find the ratio of their present ages -
(1) 11:7
(2) 9:5
(3) 7:4
(4) 7:3​

Answer 1

hope it helps you ✔️✅........ ...

Answer 2

Answer:

Step-by-step explanation:

Given :-

Ten years ago, the age of mother was three times the age of her son.

After ten years, mother's age will be twice that of his son.

To Find :-

Their Present Age

Solution :-

Let the present age of Mother be x years.

And the present age of Son be y years.

Ages 10 years ago

Mother Age = x - 10 years

Son Age = y - 10 years

⇒ x - 10 = 3 ( y - 10)

⇒ x - 10 = 3y - 30

⇒ x - 3y = - 30 + 10

⇒ x - 3y = - 20 ....(1 )

Ages after 10 years :-

Mother = x + 10 years

Son = y + 10 years

Representing the condition mathematically.

⇒ x + 10 = 2 ( y + 10)

⇒ x + 10 = 2y + 20

⇒ x - 2y = 20 - 10

⇒ x - 2y = 10.....(2 )

By Solving the Equations, we get

x = 70 and y = 30

Ratio =  mother : son

Ratio = 70 : 30

Ratio = 7 : 3

Hence, the ratio of their present ages 7 : 3.