Question

Ten years ago, the age of mother was three times the
age of her son. After ten years, mother's age will be
twice that of his son. Find the ratio of their present
ages-​

Answer 1

Step-by-step explanation:

hey mate mother age = 70

and sons age = 30

Answer 2

Answer:

3 : 7 or 7 : 3

Step-by-step explanation:

Let the present age of son be "S" and Mother be

"M".

Ten years ago , Son's age will be (S - 10) years.

given that,

The age of the Mother was three times the Son's age.

Hence, Mother's age = 3(S - 10)

M - 10 = 3S - 30

M = 3S - 30 + 10

M = 3S - 20 -- equation (1)

After ten years ,

Son's age = (S + 10) years

Mother's age = (M + 10) years.

And also given that,

Mother's age will be twice the age of the Son.

M + 10 = 2(S + 10)

M + 10 = 2S + 20

M = 2S + 20 - 10

M = 2S + 10 -- equation (2)

Equate both the situations,

3S - 20 = 2S + 10

3S - 2S = 10 + 20

S = 30 years

Substitute the value of S in equation (1).

M = 3S - 20

M = 3(30) - 20

M = 90 - 20

M = 70 years.

Ratio of Son's age to Mother's age (or) Mother's age to Son's age = 30/70 (or) 70/30

Therefore, the ratio of their present ages is 3:7 or 7:3.