Math, asked by amysteriousstudent, 3 months ago

Ten years ago, the age of the mother was three times the age of her son. After 10 years, mother’s age will be twice that of her son. Find the ratio of their present ages.

Answers

Answered by dhruvi70
2

Answer:

Say, the age of son was x and mother's age was 3x. After ten years: Mother's age will be (3x + 10) +10 and son's age will be (x + 10) + 10. Given that, mother's age is twice that of son after ten years. (3x + 10): (x + 10) = 70: 30 = 7: 3.

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