Question

ten years ago the average age of a family of four members was 24 years. in these ten years two children were born and the average age of the family is the same today. what are the present age of these two children assuming that the difference in their age is 2years​

Answer 1

Answer: The elder child Age is 3 and small child age is 1

Step-by-step explanation:

Total age of 4 members, 10 years ago = (24 x 4) years = 96 years.

Total age of 4 members now = [96 + (10 x 4)] years = 136 years.

Total age of 6 members now = (24 x 6) years = 144 years.

Sum of the ages of 2 children = (144 - 136) years = 8 years.

Let the age of the younger child be x years.

Then, The age of the elder child = (x+2) years.

So, x+(x+2) =8 <=> x=3

Age of younger child  =  3 years.

Answer 2

3 years……….is the answer……..