Question

Ten years ago ,the father was six times as old as his daughter .After 10 years ,he will be twice as old as his daughter. find their present ages.

Let present age of daughter=D
Let present age of father=F
According to question
F−10=6(D−10)
F−10=6D−60
F=6D−50−(1)
F+10=2(D+10)
F+10=2D+20
D=15years
F=6x15-50=40years
ans

Answer 1

Answer:

present ages are

daughter 15 and

father. 40 years