Math, asked by ajaysahu3060, 4 months ago

ten years ago the father was six times as old as his daughter. After 10 years,he will be twice as old as his daughter. find their present ages. ​

Answers

Answered by PRASENJITGAMER
0

Answer:

Let the present age of father and his daughter are x and y respectively.Given that ten years ago a father was six times as old as his daughter. ( x - 10 ...

Answered by Anonymous
3

Answer:

Daughter = 15 years

Father = 40 years

Step-by-step explanation:

Let present age of daughter = D

Let present age of father = F

F - 10 = 6 ( D - 10 )

F - 10 = 6D - 60

F = 6D - 50 - (1)

F + 10 = 2( D + 10 )

F + 10 = 2D + 20

D = 15

F = 6*15 -50

= 40

I hope this will be help you.

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