Question

Ten years ago, the ratio of ages of A and B was 3 : 5. The ratio of their present ages is 2 : 3. Their respective ages in years are? ​

Answer 1

Step-by-step explanation:

Let the age before 10 years is a then after 10 years it will be a+10

Let present age of A be a

and present age of B be b

then

b/a = 3/2

a = 3/ 2b ----(i)

Before 10 years,

b−10/ a−10 = 5/3

or, 5a−50 = 3b−30

or, 5a−3b=20 ----(ii)

Using equation (i) and (ii)

(5) (2b/3) - 3b = 20

or, 10b−9b=20×3

b =60 and a=40.

the differences between the two ages is 20 years.

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