Question

ten years ago the son's age was twice of the daughter's age now the son's age is 3 years more than the ​daughter's age find the present ages

Answer 1

Solution

Given :-

• ten years ago the son's age was twice of the daughter's age
• the son's age is 3 years more than the daughter's age

Find :-

• Present age of son & daughter

Explanation

Let,

• Present age of son = x years
• Present age of daughter = y years

Case(1).

(ten years ago the son's age was twice of the daughter's age)

➡(x-10) = 2 × (y-10)

➡x - 2y = -20 + 10

➡x - 2y = -10_________(1)

Case(2).

(the son's age is 3 years more than the daughter's age)

➡x = y + 3

➡x - y = 3_________(2)

Subtract equ(1) & equ(2)

➡-2y + y = -10 - 3

➡-y = -13

➡y = 13

Keel in equ(1).

➡x - 2 × 13 = -10

➡x = -10 + 26

➡x = 16

Hence

• Present age of son = 16 years
• Present age of daughter = 13 years

__________________

Answer 2

Answer:

the son age is 16 year

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