Question

Ten years back, mother was 12 times as old as her daughter and ten years hence she will be twice as old as her daughter will be. Find the present ages

Answer 1

Let the present age of Mother = x years

and present age of his daughter = y years

Case 1:

(x - 10) = 12(y - 10)

⇒ x - 10 = 12y - 120

⇒ x - 12y = -110 .... (1)

Case 2:

 (x + 10) = 2(y + 10)

⇒ x - 2y = 10 .... (2)

On subtracting (2) from (1), we get

 x - 12y - (x - 2y) = -110 - 10

⇒ - 10y = -120

⇒ y = 12

On putting y in (2), we get

x - 24 = 10

⇒ x = 34 

Hence, age of Mother = x = 34 years and 

age of his daughter = y = 12 years







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