Math, asked by jenniferpachakma, 2 months ago

Ten years earlier the age of sanjays father was three times the age of sanjay.at present sanjay age is 32 years younger than his father. find their present agees.​

Answers

Answered by Anonymous
60

Answer :-

Let the present age of sanjay be x.

His father's age = x + 32

Ten year's ago -

Sanjay age = x - 10

Father's age = x + 22

According to the question -

➩ x + 22 = 3 ( x - 10 )

➩ x + 22 = 3x - 30

➩ 3x - x = 30 + 22

➩ 2x = 52

➩ x = 26

Present age of sanjay = 26 years

Present age of his father = 26 + 32 = 58 years

Answered by Anonymous
334

Given :-

  • Let the present age of Sanjay be x. His father's age = x + 32

To find :-

  • Ten years ago.

Solution :-

  • Sanjay age = x - 10
  • Father's age = x + 22

  • According to the question

→ x + 22 = 3 (x - 10)

→ x + 22 = 3x - 30

→ 3x - x = 30 + 22

→ 2x = 52

→ x = 26

Present age of Sanjay = 26 years

Hence,

  • Present age of his father = 26 + 32 = 58 years.
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