Question

Ten years from now, A will be twice as old as B. Five years ago, A was three times as old as B. What are the present ages of A and B?

Answer 1

now a age is 15 and b age is 18

Answer 2

Equations:
a+10 = 2(b+10)
a-5 = 3(b-5)
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Rearrange:
a - 2b = 10
a - 3b = -10


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Subtract and solve for "b":
b = 20 (B's age now)
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Solve for "a" using a = 2b + 10
a = 2*20+10 = 50 (A's age now)
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