Question

Ten years hence, a man's age will be twice the age of his son. Ten years ago, the man was four times as old as his son. Find their present ages.

Answer 1

Answer:

X-10 =4(x-10)

X+10=2(x+10)

X=4x-40+10

X=2x+10

2x+10=4x-30

2x=40

X =20

Son age 20 man age 30