Ten years later A will be twice as old as B and five years ago A was three times as old as B.what is the present age of B?
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Step-by-step explanation:
Let the ages of A and B be x and y years.
According to first condition
x+10=2(y+10)
x+10=2y+20
x-2y=10...(1)
From second condition
x-5=3(y-5)
x-5=3y-15
x-3y=-10...(2)
eq(1)-eq(2)
y=20
Sunstitute y=20 in eq(1)
x-2(20)=10
x-40=10
x=10+40=50
The ages of A and B are 50 and 20 years respectively.
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