Question

Ten years later, A will be twice as old as B and five years ago, A was three times
as old as B. then the present ages of A and B in years?​

Answer 1

Answer:

A/C1---->B+5=2(A+5)

B=2A+ 10-5

2A-B+5=0---------【1】

A/C2----->B-5=3(A-5)

B=3A-15+5

3A-B-10=0----------【2】

Solve them by any method and get your answer

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Answer 2

Let the present age of A be X and B be Y.

After ten years, age of A will be (X+10) &B will be (Y+10).

:-

Age of A = Twice age of B

x+10=2(y+10)

X-2y=10 ____ (1)

Also 3years ago, age of A be (x-3) & age of B be (y-3)

:-

Age of A= thrice the age of B

x-3 = 3-(y-3)

=x-3y = -6 _____ (2)

(1) &(2)

(x-2y) -(x-3y) =10-(-6)

=x-2y -x +3y= 10+6

Y=16

Now, x-2y =10

=X = 10+2 (16)

=x = 42

Hence, present age of A is 42 B is 16 years old.