Question

Ten years later, Nuri will be twice as
old as Sonu. How old are Nuri and Sonu?
Go The sum of the digits of a two-digit number is 9. Also, nine times this number is
twice the number obtained by reversing the order of the digits. Find the number.
(iv) Meena went to a bank to withdraw * 2000. She asked the cashier to give her​

Answer 1

Answer:

x=50

Step-by-step explanation:

Let the present age of Nuri  = x year

And present age of Sonu = y year

Five years ago

Age of Nuri = x – 5 years

Age of Sony = y – 5 years

Nuri was thrice as old as Sonu

x- 5  =  3(y – 5)

x – 5  =  35 – 15

x – 3y  =  -15  + 5

x – 3 y  = - 10                        ………..(1)

Ten years later,

Age of Nuri  = x + 10

Age of Sonu = y + 10

Nuri will be twice as old as Sonu.

x+ 10 = 2(y+10)

x + 10  = 2y + 20

x – 2y  = 10                           ………..(2)

x – 3 y  = - 10                        ………..(1)

Subtracting equation (1) from equation (2)  we get

y  = 20

Plug this value in equation first we get

x  - 3* 20 = -10

x = 60 – 10

x=50

Answer 2

$\huge\sf{\underline{\underline{Solution:}}}$

Given :-

The sum of digits f a two digit number is 9.

Also nine times this number is twice the number obtained by reversing the order of digit.

To Find :-

The Number

Let the unit digit and tens digits of the number be x and y

Number = 10y + x

Number after reversing the digits = 10x + y

A.T.Q

⇒ x + y = 9 ... (i)

⇒ 9(10y + x) = 2(10x + y)

⇒ 88y - 11x = 0

⇒ -x + 8y =0 ... (ii)

Adding equation (i) and (ii), we get

⇒ 9y = 9

⇒ y = 1 ... (iii)

Putting the value in equation (i), we get

⇒ x = 8

Hence

the number is 10y + x = 10 × 1 + 8 = 18.