Question

Ten years years ago father was 12 times as old as his son and 10 years hence he will be twice as old his son will be find their present age.​

Answer 1

Answer:

find answer in attachment

Answer 2

${\huge{\underline{\underline{\rm{SolutiOn:}}}}}$

Let x and y be the present age of father and son respectively.

Then According to the given conditions ,we have

x - 10 = 12(y - 10)

➪ x -12y +110 = 0.............(1)

Also,

x + 10 = 2(y + 10)

➪ x - 2y - 10 = 0.............(2)

${\bf{\red{Subtracting\:(2)\:from\:(1),we\:get}}}$

-10y + 120 = 0

➪-10y = -120

➪y = 12

${\bf{\blue{Putting\:this\:value\:of \:y\:in\:(1), we\:get}}}$

${\huge{\boxed{ x = 34}}}$

${\bf{\green{Hence,\:the\: present\:age\:of\:his\:father\:is\:34years\:and\: present\:age\:of\:son\:is\:12years}}}$