Tenesha is trying to draw a parallelogram and find its area using the two line segments shown.
On a coordinate plane, 2 line segments are formed by points (1, 5), (5, 2), (12, 2).
She begins by finding the missing vertex on the graph to be point (9, 5). Then she calculates the area of the parallelogram. What errors did she make? Check all that apply.
On a coordinate plane, a parallelogram is formed by the points (1, 5), (5, 2), (12, 2). and fourth point unlabeled. A = (8) (5). A = 40.
She did not find the correct vertex; it should be at (8, 5).
She used the wrong area formula; it should be A = one-half b h.
She used the wrong length for the base; it should be 7, like the given base.
She used a side length of the parallelogram for the height instead of a line segment perpendicular to the base; the height should be 3.
She should have found a segment for the top that was not parallel to the bottom. i need answer asap..plz help meeeeee
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Answer:
The answer would be A. 1 1/5
48/40 = 1 8/40
1 8/40 Simplify to 1 1/5
Hope this helps!
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