Question

Tennetiraj sir please answer my question

(x-1) (x+3) (x-2) (x-6)+36=0​

Answer 1

Given:- [(x-1) (x+3)] × [(x-2) (x-6)]+36=0

Solution:- [x²+3x-x-3] × [x²-6x-2x+12] +36=0

[x²+2x-3] × [x²-8x+12] +36=0

x⁴-8x³+12x²+2x³-16x²+24x-3x²+24x-36+36=0

x⁴-8x³+2x³+12x²-16x²-3x²+24x+24x=0

x⁴-6x³-7x²+48x=0

Now Factorise with yourself.

I helped you approx 98%.

Answer 2

Answer:

hello yar how are you what's your name