tenQ=a/b,then find the value of (cosQ+sinQ)/(cosQ-sinQ)
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Answer:wait I am writing.
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Answer:
tanQ=sinQ/cosQ=a/b
sinQ=a
cosQ=b
(cosQ+sinQ)(cosQ-sinQ)=(b+a)(b-a)=b²-a²
Step-by-step explanation:
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