Question

Tens digit of a two digit no. is 5 greater than the unit digit. If the no. are reversed the new no. is less than the original no. by 45 If the sumof digits are 9then find the digit​

Answer 1

Answer:

gkdgsgksgk the wedding and I will be in

Answer 2

Step-by-step explanation:

let X be the tens place digit and Y be the units place digit

original numbers = 10 X + Y

by condition 1

x=y+5

x-y=5 eq.1

reverse numbers = 10 Y + x

10y+x+45=10x+y

by condition 2

x+y=9 eq.2

adding eq.1 and eq.2

x+y=9

+ x-y=5

2x=14

x=14/2

x=7

put x = 7 in equation 1

x-y=5

7-y=5

7-5=y

y=2

original number = 10x+y

=10×7+2

=70+2

=72

reverse number = 10 Y + x

=10×2+7

=20+7

=27