Question

tens digit of a two digit number is 3 more than its unit digit . the sum of the original number and the number formed by reversing its digit is 55. find the numbers.​

Answer 1

Step-by-step explanation:

Let the one's digit be y

and let the ten's digit be x

so the number is 10x + y

according to the question ,

x = 3+ y ---------- (1)

the number formed by reversing its digits will be 10y + x

so,

10x +y + 10y + x = 55

11x + 11y = 55 -----------(2)

on solving both equations 1 and 2 , we get ,

x = 4

y = 1

Answer 2

Answer:

Original number = 41

Reversed number = 14

Step-by-step explanation:

Given:

• Tens digit is 3 more than the the unit digit
• Sum of the original number and reversed number is 55

To Find:

• The numbers

Solution:

Let us assume the ten's digit of the number as x

Let us assume the one's digit of the number as y

By given,

x = 3 + y----(1)

Hence the original number will be,

The original number = 10x + y

Now,

The reversed number = 10y + x

By given,

10x + y + 10y + x = 55

Now substitute the value of x from equation 1

10 (3 + y) + y + 10y + 3 + y = 55

30 + 10y + y + 10y + 3 + y = 55

22y + 33 = 55

22y = 55 - 33

22y = 22

    y = 22/22

    y = 1

Hence the digit in the unit's place is 1

Now substitute the value of y in equation 1

x = 3 + 1

x = 4

Hence the digit in the ten's place is 4

Therefore,

The original number = 10x + y

The original number = 10 × 4 + 1 = 41

Therefore the original number is 41

The reversed number is given by,

Reversed number = 10y + x

Reversed number = 10 × 1 + 4 = 14

Hence the reversed number is 14

Verification:

Ten's digit = One's digit + 3

4 = 1 + 3

4 = 4

Original number + Reversed number = 55

41 + 14 = 55

55 = 55

Hence verified.