Tenth place digit of a two digit number is three times of the other digit. If you interchange the digits of this two digit number and add the resulting number to the original number, you get 88. What is the original number?
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Answer:
The original number is 62.
Step-by-step explanation:
Solution :
Let,
- Ones digit = x
- Tens digit = 3x
★ Original number :
⇒ 10 (3x) + x
⇒ 30x + x
⇒ 31x
★ On interchanging digits new number :
⇒ 10 (x) + 3x
⇒ 10x + 3x
⇒ 13x
★ According to the Question :
⇒ 31x + 13x = 88
⇒ 44x = 88
⇒ x = 88/44
⇒ x = 2
Ones digit = 2
• Tens digit = 3x
⇒ 3 × 2
⇒ 6
Tens digit = 6
(Original number : 31x = 31 × 2 = 62)
The original number = 62
Therefore, the original number is 62.
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