Question

tenth term from the end of the AP 18,16,14–––––– –10 is​

Answer 1

Answer:

12 is the correct answer

Thanks me later

Answer 2

Given,

A.P., $\[18,16,14, - - - - - , - 10\]$

Solution,

Know that formula for nth term of A.P. whose first term is a and common difference is d.

$\[{a_n} = a + \left( {n - 1} \right)d\]$

Calculate the tenth term of given A.P.

$\[\begin{array}{l}{a_{10}} = 18 + \left( {10 - 1} \right)\left( { - 2} \right)\\{a_{10}} = 18 + 9 \times \left( { - 2} \right)\\{a_{10}} = 18 - 18\\{a_{10}} = 0\end{array}\]$

Hence the 10th term of A.P. is 0.