Tentukan posisi titik (5,-6) terhadap lingkaran x²+y²=25 ???
A.pda lingkaran
B.di dalam lingkaran
C.diluar lingkaran
D.tidak dapat ditentukan
Answers
Given : lingkaran (circle) x²+y²=25
To find : Determine the position of points (5, -6) , Tentukan posisi titik (5,-6)
Solution:
Determine the position of points (5, -6) with respect to the circle x² + y² = 25 ???
A. circle
B.in the circle
C. outside the circle
D. cannot be determined
x² + y² = 25
=> x² + y² = 5²
(x - h)² + (y - k)² = r²
=> center of circle = (0 , 0)
pusat lingkaran =(0 , 0)
& radius = 5
Point ( 5 , -6) distance from center of circle
= √(5 - 0)² + (-6-0)²
= √25 + 36
= √61 > 5
Distance is more than radius
A point, whose distance from the centre of a circle is greater than its radius lies in Exterior of the circle
Hence point lies outside circle
170/5000
Jarak lebih dari radius
Suatu titik, yang jaraknya dari pusat lingkaran lebih besar dari jari-jarinya terletak di Eksterior lingkaran
Karenanya titik terletak di luar lingkaran
C. diluar lingkaran
Learn more:
A point, whose distance from the centre of a circle is greater than its ...
https://brainly.in/question/5714833
Ramya Said the length of the tangent of a circle with o from point p ...
https://brainly.in/question/14691959