Question

tep 3 Re
given numbers.
> 3.3
le 3: Find the HCF of 144, 252 and 330 by continued division method.
Now, we find the HCF of 36 and 04,
n:
the
he H
44, 1
First we find the HCF of 144 and 252.
144) 252 (
- 144
108) 144
108
36 ) 108 (3
the
36) 330
- 324
Last Divisor
>6) 3616
36
- 108
75
Last Divisor
0+--Remainder
So, the HCF of 144, 252 and 330 is 6.
O Ren​

Answer 1

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