Tert butyl chloride reacts with aqueous sodium hydroxide by sn1 while n-butyl
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Answer: Tert-butyl chloride reacts with aqueous sodium hydroxide by Sn1 while n-butyl don't because the reactivity series of Sn1 is 3°>2°>1°>Ch₃(with free radical).
N-butyl is 1° so, it will go through Sn2 Reaction whose reactivity series is Ch₃(with free radical)>1°>2°>3°.
In 3° the carbo cation gets the support from three sides (as alkyl groups are electron pushhing) thus, it gives Sn1 easily while 1° only gets support from one side thus it gives Sn2 Reaction.
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