Tert butyl chloride reacts with aqueous sodium hydroxide by sn1 mechanism while n-butyl chloride reacts by sn1 mechanism
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question is slightly wrong because second case follows by sn2 not sn1.
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Cl is bonded to Tertiary C-atom in case of Ter butyl chloride whereas in n-butyl chloride, Cl is bonded to primary C-atom. Due to high stability of carbocation formation and high steric hindrance in first case, it follows sn1 and in second case due to low stability and less steric hindrance it follows sn2.
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Well, I have given a huge explanation below but you can shorten it down according to the marks alloted for the question.
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