Math, asked by adityachaurasia307, 6 months ago

Test 341, 94, 960 and 1281 for divisibility by 2, 3, 5 and 10​

Answers

Answered by JuniorBrainly100
11

\huge\mathfrak\red{Answer}

Test divisibility by 2

341 - not divisible

94- divisible

960- divisible

1281- not divisible

\small\mathfrak{Explanation}

To test divisibility by 2:-

See the once place of the whole number.

If it is even then the number is divisible by 2.

  • In first number i,e., 341 the once place has number 1 hence it is not divisible by 2.

  • In second number 94 the number 4 is divisible by 2 hence the number is divisible by 2.

  • In third also the last number is 0 that and 0 is an even number hence it is divisible by 2 and also the number 960 is divisible by 2.

  • The last number of 1281 is 1 and one is not divisible by 2 hence the whole number 1281 is not divisible by 2.

\huge\mathfrak\red{Answer}

Test divisibility by 3:-

1)341- not divisible

2)94- not divisible

3)960- divisible

4)1281- divisible

\small\mathfrak{Explanation}

\small\bold\brown{To \ test \ divisibility \ by \ 3}

Add all the \small\bold{Numbers} and then if the additional value came is divisible by 3 that means that the wgole numbers is \huge\bold\red{divisible} by \small\bold\red{3}

  • In first case the number \small\bold\pink{314} when added up gives 8 which is not divisible by 3 hence tge number too is \small\bold\pink{not \ divisible} by \small\bold\pink{3}
  • in second case the number 94's sum is 13 which is not divisible by 3 that means 94 is also \small\bold\pink{not \ divisible} by \small\bold\pink{3} .
  • Third number is \small\bold\pink{divisible} as the sum of the number is dividible by 3.
  • Fourth nunber is also divisible as it's sum too is divisible by 3.

\small\mathfrak{Answer}

Test divisibility by 5:-

341- not divisible

94- not divisible

960- divisible

1281- not divisible

\small\mathfrak{Explanation}

To test divisibility by 5 just the onse place of the number sould either be 0 or 5.

  • In first case the number was 1 hence it was \small\bold\pink{not \ divisible} by 5.
  • In second also there was 4 hence \small\bold\pink{not \ divisible} by 5
  • in third the number was 0 hence \small\bold\pink{divisible} .
  • In fourth also \small\bold\pink{not \ divisible} .

\small\mathfrak{Answer}

Test divisibility by 10:-

341- not divisible

94-not divisible

960-divisible

1281-not divisible.

\small\mathfrak{Explanation}

To check divisibility by 10 the last number must be zero (0).

only option 3 has 0 in last hence it is only divisible by 10.

Hope it helped.

Mark brainliest please..

Thank you...

Answered by KrishnaKumar01
1

Answer:

2 - can be. Divide by only those numbers in which ends at even number.

3- can be divided by when all the sum of number can be divided by 3.

5- can be divided by those numbers in which ends at 0 or 5 only.

10- can be divided by only those number in. Which ends at 0 only.

Step-by-step explanation:

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